Base | Representation |
---|---|
bin | 1001000011100001101… |
… | …00000100101001001101 |
3 | 1002202002012122002100120 |
4 | 10201300310010221031 |
5 | 20044143332002023 |
6 | 354533055015153 |
7 | 31323046201026 |
oct | 4416064045115 |
9 | 1082065562316 |
10 | 311130344013 |
11 | 10aa49a71515 |
12 | 50370b0a4b9 |
13 | 23454a62498 |
14 | 110b7461c4d |
15 | 815e8e88e3 |
hex | 4870d04a4d |
311130344013 has 8 divisors (see below), whose sum is σ = 415324523328. Its totient is φ = 207178197024.
The previous prime is 311130343987. The next prime is 311130344039. The reversal of 311130344013 is 310443031113.
It is an interprime number because it is at equal distance from previous prime (311130343987) and next prime (311130344039).
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 311130344013 - 25 = 311130343981 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311130344513) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60505081 + ... + 60510222.
It is an arithmetic number, because the mean of its divisors is an integer number (51915565416).
Almost surely, 2311130344013 is an apocalyptic number.
It is an amenable number.
311130344013 is a deficient number, since it is larger than the sum of its proper divisors (104194179315).
311130344013 is a wasteful number, since it uses less digits than its factorization.
311130344013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 121016163.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 311130344013 its reverse (310443031113), we get a palindrome (621573375126).
The spelling of 311130344013 in words is "three hundred eleven billion, one hundred thirty million, three hundred forty-four thousand, thirteen".
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