Base | Representation |
---|---|
bin | 1110001001100000101010… |
… | …11110001101011010001001 |
3 | 11002011101100122222210220112 |
4 | 13010300111132031122021 |
5 | 13034224113423124001 |
6 | 150101055022404105 |
7 | 6360563463534614 |
oct | 704602536153211 |
9 | 132141318883815 |
10 | 31113103333001 |
11 | 9a05aa1795078 |
12 | 35a5b17430635 |
13 | 1448c50b28ab1 |
14 | 797c4cbdb17b |
15 | 38e4cacddcbb |
hex | 1c4c1578d689 |
31113103333001 has 2 divisors, whose sum is σ = 31113103333002. Its totient is φ = 31113103333000.
The previous prime is 31113103332953. The next prime is 31113103333007. The reversal of 31113103333001 is 10033330131113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28764976163401 + 2348127169600 = 5363299^2 + 1532360^2 .
It is a cyclic number.
It is not a de Polignac number, because 31113103333001 - 222 = 31113099138697 is a prime.
It is not a weakly prime, because it can be changed into another prime (31113103333007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15556551666500 + 15556551666501.
It is an arithmetic number, because the mean of its divisors is an integer number (15556551666501).
Almost surely, 231113103333001 is an apocalyptic number.
It is an amenable number.
31113103333001 is a deficient number, since it is larger than the sum of its proper divisors (1).
31113103333001 is an equidigital number, since it uses as much as digits as its factorization.
31113103333001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 729, while the sum is 23.
Adding to 31113103333001 its reverse (10033330131113), we get a palindrome (41146433464114).
The spelling of 31113103333001 in words is "thirty-one trillion, one hundred thirteen billion, one hundred three million, three hundred thirty-three thousand, one".
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