3111313100123 has 2 divisors, whose sum is σ = 3111313100124. Its totient is φ = 3111313100122.

The previous prime is 3111313100117. The next prime is 3111313100141. The reversal of 3111313100123 is 3210013131113.

3111313100123 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 3111313100123 - 2⁶ = 3111313100059 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3111313100095 and 3111313100104.

It is not a weakly prime, because it can be changed into another prime (3111313100173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555656550061 + 1555656550062.

It is an arithmetic number, because the mean of its divisors is an integer number (1555656550062).

Almost surely, 2^{3111313100123} is an apocalyptic number.

3111313100123 is a deficient number, since it is larger than the sum of its proper divisors (1).

3111313100123 is an equidigital number, since it uses as much as digits as its factorization.

3111313100123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 3111313100123 its reverse (3210013131113), we get a palindrome (6321326231236).

The spelling of 3111313100123 in words is "three trillion, one hundred eleven billion, three hundred thirteen million, one hundred thousand, one hundred twenty-three".