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3111412003103 = 531372039210157
BaseRepresentation
bin101101010001101110100…
…110110111000100011111
3102000110002122121102221102
4231101232212313010133
5401434132433044403
610341210221223315
7440535455441465
oct55215646670437
912013078542842
103111412003103
11a9a5a6a636a8
12423019701b3b
1319753571bab1
14aa843834835
1555e057a2b88
hex2d46e9b711f

3111412003103 has 16 divisors (see below), whose sum is σ = 3194838728640. Its totient is φ = 3028922946816.

The previous prime is 3111412003093. The next prime is 3111412003121. The reversal of 3111412003103 is 3013002141113.

3111412003103 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 3111412003103 - 214 = 3111411986719 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3111412002103) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14700101 + ... + 14910257.

It is an arithmetic number, because the mean of its divisors is an integer number (199677420540).

Almost surely, 23111412003103 is an apocalyptic number.

3111412003103 is a deficient number, since it is larger than the sum of its proper divisors (83426725537).

3111412003103 is a wasteful number, since it uses less digits than its factorization.

3111412003103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 212386.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 3111412003103 its reverse (3013002141113), we get a palindrome (6124414144216).

The spelling of 3111412003103 in words is "three trillion, one hundred eleven billion, four hundred twelve million, three thousand, one hundred three".

Divisors: 1 53 137 2039 7261 108067 210157 279343 11138321 14805179 28791509 428510123 1525949977 22711036519 58705886851 3111412003103