Base | Representation |
---|---|
bin | 101101010001101110101… |
… | …000011010111001100011 |
3 | 102000110002200101012211212 |
4 | 231101232220122321203 |
5 | 401434133034141003 |
6 | 10341210234100335 |
7 | 440535462063560 |
oct | 55215650327143 |
9 | 12013080335755 |
10 | 3111412412003 |
11 | a9a5a7212935 |
12 | 42301987a6ab |
13 | 197535832c4c |
14 | aa8438dd867 |
15 | 55e05833dd8 |
hex | 2d46ea1ae63 |
3111412412003 has 4 divisors (see below), whose sum is σ = 3555899899440. Its totient is φ = 2666924924568.
The previous prime is 3111412411979. The next prime is 3111412412077. The reversal of 3111412412003 is 3002142141113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3111412412003 - 28 = 3111412411747 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3111412412003.
It is not an unprimeable number, because it can be changed into a prime (3111412412083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 222243743708 + ... + 222243743721.
It is an arithmetic number, because the mean of its divisors is an integer number (888974974860).
Almost surely, 23111412412003 is an apocalyptic number.
3111412412003 is a deficient number, since it is larger than the sum of its proper divisors (444487487437).
3111412412003 is an equidigital number, since it uses as much as digits as its factorization.
3111412412003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 444487487436.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 3111412412003 its reverse (3002142141113), we get a palindrome (6113554553116).
The spelling of 3111412412003 in words is "three trillion, one hundred eleven billion, four hundred twelve million, four hundred twelve thousand, three".
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