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3111412412003 = 7444487487429
BaseRepresentation
bin101101010001101110101…
…000011010111001100011
3102000110002200101012211212
4231101232220122321203
5401434133034141003
610341210234100335
7440535462063560
oct55215650327143
912013080335755
103111412412003
11a9a5a7212935
1242301987a6ab
13197535832c4c
14aa8438dd867
1555e05833dd8
hex2d46ea1ae63

3111412412003 has 4 divisors (see below), whose sum is σ = 3555899899440. Its totient is φ = 2666924924568.

The previous prime is 3111412411979. The next prime is 3111412412077. The reversal of 3111412412003 is 3002142141113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3111412412003 - 28 = 3111412411747 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3111412412003.

It is not an unprimeable number, because it can be changed into a prime (3111412412083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 222243743708 + ... + 222243743721.

It is an arithmetic number, because the mean of its divisors is an integer number (888974974860).

Almost surely, 23111412412003 is an apocalyptic number.

3111412412003 is a deficient number, since it is larger than the sum of its proper divisors (444487487437).

3111412412003 is an equidigital number, since it uses as much as digits as its factorization.

3111412412003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 444487487436.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 3111412412003 its reverse (3002142141113), we get a palindrome (6113554553116).

The spelling of 3111412412003 in words is "three trillion, one hundred eleven billion, four hundred twelve million, four hundred twelve thousand, three".

Divisors: 1 7 444487487429 3111412412003