3111412412083 has 2 divisors, whose sum is σ = 3111412412084. Its totient is φ = 3111412412082.

The previous prime is 3111412412081. The next prime is 3111412412099. The reversal of 3111412412083 is 3802142141113.

It is a weak prime.

It is an emirp because it is prime and its reverse (3802142141113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3111412412083 - 2¹ = 3111412412081 is a prime.

Together with 3111412412081, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (3111412412081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555706206041 + 1555706206042.

It is an arithmetic number, because the mean of its divisors is an integer number (1555706206042).

Almost surely, 2^{3111412412083} is an apocalyptic number.

3111412412083 is a deficient number, since it is larger than the sum of its proper divisors (1).

3111412412083 is an equidigital number, since it uses as much as digits as its factorization.

3111412412083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 31.

Adding to 3111412412083 its reverse (3802142141113), we get a palindrome (6913554553196).

The spelling of 3111412412083 in words is "three trillion, one hundred eleven billion, four hundred twelve million, four hundred twelve thousand, eighty-three".