Base | Representation |
---|---|
bin | 1110001001100010111100… |
… | …10100011011010100100011 |
3 | 11002011111111211201121010210 |
4 | 13010301132110123110203 |
5 | 13034234114312132230 |
6 | 150101420202025203 |
7 | 6360635664040323 |
oct | 704613624332443 |
9 | 132144454647123 |
10 | 31114325505315 |
11 | 9a06569665238 |
12 | 35a61b87a8203 |
13 | 14490b70b4390 |
14 | 797d2725d283 |
15 | 38e54d258eb0 |
hex | 1c4c5e51b523 |
31114325505315 has 64 divisors (see below), whose sum is σ = 54777253902336. Its totient is φ = 14985287572992.
The previous prime is 31114325505311. The next prime is 31114325505317. The reversal of 31114325505315 is 51350552341113.
It is not a de Polignac number, because 31114325505315 - 22 = 31114325505311 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is not an unprimeable number, because it can be changed into a prime (31114325505311) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 20028289 + ... + 21525821.
It is an arithmetic number, because the mean of its divisors is an integer number (855894592224).
Almost surely, 231114325505315 is an apocalyptic number.
31114325505315 is a deficient number, since it is larger than the sum of its proper divisors (23662928397021).
31114325505315 is a wasteful number, since it uses less digits than its factorization.
31114325505315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1499868.
The product of its (nonzero) digits is 135000, while the sum is 39.
Adding to 31114325505315 its reverse (51350552341113), we get a palindrome (82464877846428).
The spelling of 31114325505315 in words is "thirty-one trillion, one hundred fourteen billion, three hundred twenty-five million, five hundred five thousand, three hundred fifteen".
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