3111503113 has 2 divisors, whose sum is σ = 3111503114. Its totient is φ = 3111503112.

The previous prime is 3111503069. The next prime is 3111503147. The reversal of 3111503113 is 3113051113.

3111503113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2365557769 + 745945344 = 48637^2 + 27312^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3111503113 is a prime.

It is not a weakly prime, because it can be changed into another prime (3111503513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555751556 + 1555751557.

It is an arithmetic number, because the mean of its divisors is an integer number (1555751557).

Almost surely, 2^3111503113 is an apocalyptic number.

It is an amenable number.

3111503113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3111503113 is an equidigital number, since it uses as much as digits as its factorization.

3111503113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135, while the sum is 19.

The square root of 3111503113 is about 55780.8489806313. The cubic root of 3111503113 is about 1459.9010242844.

Adding to 3111503113 its reverse (3113051113), we get a palindrome (6224554226).

The spelling of 3111503113 in words is "three billion, one hundred eleven million, five hundred three thousand, one hundred thirteen".