Base | Representation |
---|---|
bin | 101101010010001100111… |
… | …000110110101010000011 |
3 | 102000111102001120012201112 |
4 | 231102030320312222003 |
5 | 401441203012131413 |
6 | 10341332450153535 |
7 | 440554164604406 |
oct | 55221470665203 |
9 | 12014361505645 |
10 | 3111920036483 |
11 | a9a8378076a5 |
12 | 42313b8828ab |
13 | 1975b6a5756b |
14 | aa8910bbd3d |
15 | 55e351a62a8 |
hex | 2d48ce36a83 |
3111920036483 has 2 divisors, whose sum is σ = 3111920036484. Its totient is φ = 3111920036482.
The previous prime is 3111920036479. The next prime is 3111920036507. The reversal of 3111920036483 is 3846300291113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3111920036483 - 22 = 3111920036479 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3111920036483.
It is not a weakly prime, because it can be changed into another prime (3111920026483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555960018241 + 1555960018242.
It is an arithmetic number, because the mean of its divisors is an integer number (1555960018242).
Almost surely, 23111920036483 is an apocalyptic number.
3111920036483 is a deficient number, since it is larger than the sum of its proper divisors (1).
3111920036483 is an equidigital number, since it uses as much as digits as its factorization.
3111920036483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 41.
The spelling of 3111920036483 in words is "three trillion, one hundred eleven billion, nine hundred twenty million, thirty-six thousand, four hundred eighty-three".
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