Base | Representation |
---|---|
bin | 101101010010010001101… |
… | …111110001010001100111 |
3 | 102000111121201221002012121 |
4 | 231102101233301101213 |
5 | 401441334343304343 |
6 | 10341344521130411 |
7 | 440556204435511 |
oct | 55222157612147 |
9 | 12014551832177 |
10 | 3112001541223 |
11 | a9a879816393 |
12 | 423163029a07 |
13 | 1975ca8c3813 |
14 | aa89bc56bb1 |
15 | 55e3c405aed |
hex | 2d491bf1467 |
3112001541223 has 4 divisors (see below), whose sum is σ = 3117529075608. Its totient is φ = 3106474006840.
The previous prime is 3112001541193. The next prime is 3112001541239. The reversal of 3112001541223 is 3221451002113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3112001541223 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3112001541263) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2763766348 + ... + 2763767473.
It is an arithmetic number, because the mean of its divisors is an integer number (779382268902).
Almost surely, 23112001541223 is an apocalyptic number.
3112001541223 is a deficient number, since it is larger than the sum of its proper divisors (5527534385).
3112001541223 is an equidigital number, since it uses as much as digits as its factorization.
3112001541223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5527534384.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 3112001541223 its reverse (3221451002113), we get a palindrome (6333452543336).
The spelling of 3112001541223 in words is "three trillion, one hundred twelve billion, one million, five hundred forty-one thousand, two hundred twenty-three".
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