Base | Representation |
---|---|
bin | 101101010010010001110… |
… | …101101110100101101001 |
3 | 102000111121211212102200012 |
4 | 231102101311232211221 |
5 | 401441340243244311 |
6 | 10341345014421305 |
7 | 440556223632155 |
oct | 55222165564551 |
9 | 12014554772605 |
10 | 3112003103081 |
11 | a9a87a692884 |
12 | 423163661835 |
13 | 1975cb01c6b2 |
14 | aa89c142065 |
15 | 55e3c61378b |
hex | 2d491d6e969 |
3112003103081 has 2 divisors, whose sum is σ = 3112003103082. Its totient is φ = 3112003103080.
The previous prime is 3112003102993. The next prime is 3112003103119. The reversal of 3112003103081 is 1803013002113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2804338747456 + 307664355625 = 1674616^2 + 554675^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3112003103081 is a prime.
It is a super-2 number, since 2×31120031030812 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3112003103381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556001551540 + 1556001551541.
It is an arithmetic number, because the mean of its divisors is an integer number (1556001551541).
Almost surely, 23112003103081 is an apocalyptic number.
It is an amenable number.
3112003103081 is a deficient number, since it is larger than the sum of its proper divisors (1).
3112003103081 is an equidigital number, since it uses as much as digits as its factorization.
3112003103081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 3112003103081 its reverse (1803013002113), we get a palindrome (4915016105194).
The spelling of 3112003103081 in words is "three trillion, one hundred twelve billion, three million, one hundred three thousand, eighty-one".
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