Base | Representation |
---|---|
bin | 101101010010010100001… |
… | …111000100110011101010 |
3 | 102000111201122111202101120 |
4 | 231102110033010303222 |
5 | 401441431041131442 |
6 | 10341353012200110 |
7 | 440560222416426 |
oct | 55222417046352 |
9 | 12014648452346 |
10 | 3112043302122 |
11 | a9a8a0349a27 |
12 | 423175009036 |
13 | 197606455a01 |
14 | aa8a3607b86 |
15 | 55e40e044ec |
hex | 2d4943c4cea |
3112043302122 has 16 divisors (see below), whose sum is σ = 6285711225312. Its totient is φ = 1027076997200.
The previous prime is 3112043302091. The next prime is 3112043302129. The reversal of 3112043302122 is 2212033402113.
It is a junction number, because it is equal to n+sod(n) for n = 3112043302092 and 3112043302101.
It is not an unprimeable number, because it can be changed into a prime (3112043302129) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2567691888 + ... + 2567693099.
It is an arithmetic number, because the mean of its divisors is an integer number (392856951582).
Almost surely, 23112043302122 is an apocalyptic number.
3112043302122 is an abundant number, since it is smaller than the sum of its proper divisors (3173667923190).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3112043302122 is a wasteful number, since it uses less digits than its factorization.
3112043302122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5135385093.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 3112043302122 its reverse (2212033402113), we get a palindrome (5324076704235).
Subtracting from 3112043302122 its reverse (2212033402113), we obtain a palindrome (900009900009).
The spelling of 3112043302122 in words is "three trillion, one hundred twelve billion, forty-three million, three hundred two thousand, one hundred twenty-two".
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