Base | Representation |
---|---|
bin | 11100111110111101… |
… | …001111100111111001 |
3 | 2222022212200021110001 |
4 | 130332331033213321 |
5 | 1002213434410431 |
6 | 22144035153001 |
7 | 2151131151013 |
oct | 347675174771 |
9 | 88285607401 |
10 | 31121013241 |
11 | 1222000095a |
12 | 6046445761 |
13 | 2c1c6c2446 |
14 | 17132971b3 |
15 | c22260e61 |
hex | 73ef4f9f9 |
31121013241 has 2 divisors, whose sum is σ = 31121013242. Its totient is φ = 31121013240.
The previous prime is 31121013193. The next prime is 31121013347. The reversal of 31121013241 is 14231012113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 29711761641 + 1409251600 = 172371^2 + 37540^2 .
It is a cyclic number.
It is not a de Polignac number, because 31121013241 - 213 = 31121005049 is a prime.
It is not a weakly prime, because it can be changed into another prime (31121013641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15560506620 + 15560506621.
It is an arithmetic number, because the mean of its divisors is an integer number (15560506621).
Almost surely, 231121013241 is an apocalyptic number.
It is an amenable number.
31121013241 is a deficient number, since it is larger than the sum of its proper divisors (1).
31121013241 is an equidigital number, since it uses as much as digits as its factorization.
31121013241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 31121013241 its reverse (14231012113), we get a palindrome (45352025354).
The spelling of 31121013241 in words is "thirty-one billion, one hundred twenty-one million, thirteen thousand, two hundred forty-one".
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