Base | Representation |
---|---|
bin | 1110001001101111100100… |
… | …01000001110101011111111 |
3 | 11002012010222222200222120101 |
4 | 13010313302020032223333 |
5 | 13034342003134144403 |
6 | 150104500333301531 |
7 | 6361265606625346 |
oct | 704676210165377 |
9 | 132163888628511 |
10 | 31121100303103 |
11 | 9a09425883078 |
12 | 35a75896348a7 |
13 | 144992684aa75 |
14 | 7983aad16b5d |
15 | 38e7e7ddb71d |
hex | 1c4df220eaff |
31121100303103 has 4 divisors (see below), whose sum is σ = 31441936388800. Its totient is φ = 30800264217408.
The previous prime is 31121100303101. The next prime is 31121100303107. The reversal of 31121100303103 is 30130300112113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31121100303103 - 21 = 31121100303101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31121100303101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160418042703 + ... + 160418042896.
It is an arithmetic number, because the mean of its divisors is an integer number (7860484097200).
Almost surely, 231121100303103 is an apocalyptic number.
31121100303103 is a deficient number, since it is larger than the sum of its proper divisors (320836085697).
31121100303103 is an equidigital number, since it uses as much as digits as its factorization.
31121100303103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 320836085696.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 31121100303103 its reverse (30130300112113), we get a palindrome (61251400415216).
The spelling of 31121100303103 in words is "thirty-one trillion, one hundred twenty-one billion, one hundred million, three hundred three thousand, one hundred three".
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