Base | Representation |
---|---|
bin | 101101010010011000001… |
… | …101101000100011100001 |
3 | 102000111220022002001010001 |
4 | 231102120031220203201 |
5 | 401442100132024441 |
6 | 10341403354340001 |
7 | 440561662546435 |
oct | 55223015504341 |
9 | 12014808061101 |
10 | 3112110033121 |
11 | a9a924a87a11 |
12 | 42319342a601 |
13 | 19761721b5cb |
14 | aa8ac4189c5 |
15 | 55e46bd6731 |
hex | 2d4983688e1 |
3112110033121 has 2 divisors, whose sum is σ = 3112110033122. Its totient is φ = 3112110033120.
The previous prime is 3112110033107. The next prime is 3112110033127. The reversal of 3112110033121 is 1213300112113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3108680291025 + 3429742096 = 1763145^2 + 58564^2 .
It is a cyclic number.
It is not a de Polignac number, because 3112110033121 - 213 = 3112110024929 is a prime.
It is not a weakly prime, because it can be changed into another prime (3112110033127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556055016560 + 1556055016561.
It is an arithmetic number, because the mean of its divisors is an integer number (1556055016561).
Almost surely, 23112110033121 is an apocalyptic number.
It is an amenable number.
3112110033121 is a deficient number, since it is larger than the sum of its proper divisors (1).
3112110033121 is an equidigital number, since it uses as much as digits as its factorization.
3112110033121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 3112110033121 its reverse (1213300112113), we get a palindrome (4325410145234).
The spelling of 3112110033121 in words is "three trillion, one hundred twelve billion, one hundred ten million, thirty-three thousand, one hundred twenty-one".
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