3112113123035 has 48 divisors (see below), whose sum is σ = 4361381309376. Its totient is φ = 2125615709952.

The previous prime is 3112113123029. The next prime is 3112113123113. The reversal of 3112113123035 is 5303213112113.

It is a de Polignac number, because none of the positive numbers 2^k-3112113123035 is a prime.

It is a super-2 number, since 2×3112113123035² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3112113122995 and 3112113123013.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 149804909 + ... + 149825681.

It is an arithmetic number, because the mean of its divisors is an integer number (90862110612).

Almost surely, 2^{3112113123035} is an apocalyptic number.

3112113123035 is a gapful number since it is divisible by the number (35) formed by its first and last digit.

3112113123035 is a deficient number, since it is larger than the sum of its proper divisors (1249268186341).

3112113123035 is a wasteful number, since it uses less digits than its factorization.

3112113123035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23172 (or 23165 counting only the distinct ones).

The product of its (nonzero) digits is 1620, while the sum is 26.

Adding to 3112113123035 its reverse (5303213112113), we get a palindrome (8415326235148).

The spelling of 3112113123035 in words is "three trillion, one hundred twelve billion, one hundred thirteen million, one hundred twenty-three thousand, thirty-five".