311211340050103 has 8 divisors (see below), whose sum is σ = 323669285422736. Its totient is φ = 298990688875200.

The previous prime is 311211340050007. The next prime is 311211340050133. The reversal of 311211340050103 is 301050043112113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 311211340050103 - 2²¹ = 311211337952951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311211340050133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59323546758 + ... + 59323552003.

It is an arithmetic number, because the mean of its divisors is an integer number (40458660677842).

Almost surely, 2^{311211340050103} is an apocalyptic number.

311211340050103 is a deficient number, since it is larger than the sum of its proper divisors (12457945372633).

311211340050103 is a wasteful number, since it uses less digits than its factorization.

311211340050103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 118647098865.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 311211340050103 its reverse (301050043112113), we get a palindrome (612261383162216).

The spelling of 311211340050103 in words is "three hundred eleven trillion, two hundred eleven billion, three hundred forty million, fifty thousand, one hundred three".