Base | Representation |
---|---|
bin | 1110001001101111110100… |
… | …01110101011100110010001 |
3 | 11002012011100110102212200102 |
4 | 13010313322032223212101 |
5 | 13034342242432241423 |
6 | 150104522030302145 |
7 | 6361302150056465 |
oct | 704677216534621 |
9 | 132164313385612 |
10 | 31121236212113 |
11 | 9a09495570573 |
12 | 35a7607057955 |
13 | 1449948a54cb8 |
14 | 7983c0db44a5 |
15 | 38e804cd5c28 |
hex | 1c4dfa3ab991 |
31121236212113 has 2 divisors, whose sum is σ = 31121236212114. Its totient is φ = 31121236212112.
The previous prime is 31121236212107. The next prime is 31121236212133. The reversal of 31121236212113 is 31121263212113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 22194717610129 + 8926518601984 = 4711127^2 + 2987728^2 .
It is a cyclic number.
It is not a de Polignac number, because 31121236212113 - 24 = 31121236212097 is a prime.
It is not a weakly prime, because it can be changed into another prime (31121236212133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15560618106056 + 15560618106057.
It is an arithmetic number, because the mean of its divisors is an integer number (15560618106057).
Almost surely, 231121236212113 is an apocalyptic number.
It is an amenable number.
31121236212113 is a deficient number, since it is larger than the sum of its proper divisors (1).
31121236212113 is an equidigital number, since it uses as much as digits as its factorization.
31121236212113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2592, while the sum is 29.
Adding to 31121236212113 its reverse (31121263212113), we get a palindrome (62242499424226).
Subtracting 31121236212113 from its reverse (31121263212113), we obtain a cube (27000000 = 3003).
The spelling of 31121236212113 in words is "thirty-one trillion, one hundred twenty-one billion, two hundred thirty-six million, two hundred twelve thousand, one hundred thirteen".
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