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31121236212113 is a prime number
BaseRepresentation
bin1110001001101111110100…
…01110101011100110010001
311002012011100110102212200102
413010313322032223212101
513034342242432241423
6150104522030302145
76361302150056465
oct704677216534621
9132164313385612
1031121236212113
119a09495570573
1235a7607057955
131449948a54cb8
147983c0db44a5
1538e804cd5c28
hex1c4dfa3ab991

31121236212113 has 2 divisors, whose sum is σ = 31121236212114. Its totient is φ = 31121236212112.

The previous prime is 31121236212107. The next prime is 31121236212133. The reversal of 31121236212113 is 31121263212113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22194717610129 + 8926518601984 = 4711127^2 + 2987728^2 .

It is a cyclic number.

It is not a de Polignac number, because 31121236212113 - 24 = 31121236212097 is a prime.

It is not a weakly prime, because it can be changed into another prime (31121236212133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15560618106056 + 15560618106057.

It is an arithmetic number, because the mean of its divisors is an integer number (15560618106057).

Almost surely, 231121236212113 is an apocalyptic number.

It is an amenable number.

31121236212113 is a deficient number, since it is larger than the sum of its proper divisors (1).

31121236212113 is an equidigital number, since it uses as much as digits as its factorization.

31121236212113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2592, while the sum is 29.

Adding to 31121236212113 its reverse (31121263212113), we get a palindrome (62242499424226).

Subtracting 31121236212113 from its reverse (31121263212113), we obtain a cube (27000000 = 3003).

The spelling of 31121236212113 in words is "thirty-one trillion, one hundred twenty-one billion, two hundred thirty-six million, two hundred twelve thousand, one hundred thirteen".