Base | Representation |
---|---|
bin | 11100111110111110… |
… | …110001100000111001 |
3 | 2222022220102122110102 |
4 | 130332332301200321 |
5 | 1002214040223301 |
6 | 22144051525145 |
7 | 2151134441003 |
oct | 347676614071 |
9 | 88286378412 |
10 | 31121414201 |
11 | 12220255129 |
12 | 60465b97b5 |
13 | 2c1c802ab7 |
14 | 171335d373 |
15 | c222deb6b |
hex | 73efb1839 |
31121414201 has 2 divisors, whose sum is σ = 31121414202. Its totient is φ = 31121414200.
The previous prime is 31121414141. The next prime is 31121414209. The reversal of 31121414201 is 10241412113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 22981044025 + 8140370176 = 151595^2 + 90224^2 .
It is an emirp because it is prime and its reverse (10241412113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31121414201 - 230 = 30047672377 is a prime.
It is not a weakly prime, because it can be changed into another prime (31121414209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15560707100 + 15560707101.
It is an arithmetic number, because the mean of its divisors is an integer number (15560707101).
Almost surely, 231121414201 is an apocalyptic number.
It is an amenable number.
31121414201 is a deficient number, since it is larger than the sum of its proper divisors (1).
31121414201 is an equidigital number, since it uses as much as digits as its factorization.
31121414201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 31121414201 its reverse (10241412113), we get a palindrome (41362826314).
The spelling of 31121414201 in words is "thirty-one billion, one hundred twenty-one million, four hundred fourteen thousand, two hundred one".
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