Base | Representation |
---|---|
bin | 100011011000011000100011… |
… | …1001011000010001110101011 |
3 | 1111210220211002022000000220101 |
4 | 1012300301013023002032223 |
5 | 311242414321212440321 |
6 | 3021521551225010231 |
7 | 122360336014541356 |
oct | 10660610713021653 |
9 | 1453824068000811 |
10 | 311214524343211 |
11 | 9018737a711665 |
12 | 2aaa3562623977 |
13 | 10486532c83258 |
14 | 56bcc1305729d |
15 | 25ea60d646791 |
hex | 11b0c472c23ab |
311214524343211 has 2 divisors, whose sum is σ = 311214524343212. Its totient is φ = 311214524343210.
The previous prime is 311214524343083. The next prime is 311214524343277. The reversal of 311214524343211 is 112343425412113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 311214524343211 - 27 = 311214524343083 is a prime.
It is a super-2 number, since 2×3112145243432112 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (311214524343511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155607262171605 + 155607262171606.
It is an arithmetic number, because the mean of its divisors is an integer number (155607262171606).
Almost surely, 2311214524343211 is an apocalyptic number.
311214524343211 is a deficient number, since it is larger than the sum of its proper divisors (1).
311214524343211 is an equidigital number, since it uses as much as digits as its factorization.
311214524343211 is an evil number, because the sum of its binary digits is even.
The product of its digits is 69120, while the sum is 37.
Adding to 311214524343211 its reverse (112343425412113), we get a palindrome (423557949755324).
The spelling of 311214524343211 in words is "three hundred eleven trillion, two hundred fourteen billion, five hundred twenty-four million, three hundred forty-three thousand, two hundred eleven".
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