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311216131 is a prime number
BaseRepresentation
bin10010100011001…
…100100000000011
3210200121102021101
4102203030200003
51114132404011
650514235231
710466202442
oct2243144003
9720542241
10311216131
1114a745316
1288285b17
134c627075
142d492d59
151c4c72c1
hex128cc803

311216131 has 2 divisors, whose sum is σ = 311216132. Its totient is φ = 311216130.

The previous prime is 311216123. The next prime is 311216149. The reversal of 311216131 is 131612113.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 311216131 - 23 = 311216123 is a prime.

It is a super-2 number, since 2×3112161312 = 193710960389218322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 311216099 and 311216108.

It is not a weakly prime, because it can be changed into another prime (311216111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155608065 + 155608066.

It is an arithmetic number, because the mean of its divisors is an integer number (155608066).

Almost surely, 2311216131 is an apocalyptic number.

311216131 is a deficient number, since it is larger than the sum of its proper divisors (1).

311216131 is an equidigital number, since it uses as much as digits as its factorization.

311216131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 108, while the sum is 19.

The square root of 311216131 is about 17641.3188565935. The cubic root of 311216131 is about 677.6738067985.

Adding to 311216131 its reverse (131612113), we get a palindrome (442828244).

The spelling of 311216131 in words is "three hundred eleven million, two hundred sixteen thousand, one hundred thirty-one".