Base | Representation |
---|---|
bin | 1110001001110001010011… |
… | …00011001010010111001001 |
3 | 11002012020101210022002001112 |
4 | 13010320221203022113021 |
5 | 13034400404202011103 |
6 | 150105132510300105 |
7 | 6361330630100153 |
oct | 704705143122711 |
9 | 132166353262045 |
10 | 31122030110153 |
11 | 9a09862713954 |
12 | 35a77a8ab7635 |
13 | 1449a4437c658 |
14 | 7984585d1ad3 |
15 | 38e84e854cd8 |
hex | 1c4e298ca5c9 |
31122030110153 has 2 divisors, whose sum is σ = 31122030110154. Its totient is φ = 31122030110152.
The previous prime is 31122030110069. The next prime is 31122030110189. The reversal of 31122030110153 is 35101103022113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23520142959049 + 7601887151104 = 4849757^2 + 2757152^2 .
It is a cyclic number.
It is not a de Polignac number, because 31122030110153 - 214 = 31122030093769 is a prime.
It is not a weakly prime, because it can be changed into another prime (31122030112153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15561015055076 + 15561015055077.
It is an arithmetic number, because the mean of its divisors is an integer number (15561015055077).
Almost surely, 231122030110153 is an apocalyptic number.
It is an amenable number.
31122030110153 is a deficient number, since it is larger than the sum of its proper divisors (1).
31122030110153 is an equidigital number, since it uses as much as digits as its factorization.
31122030110153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 31122030110153 its reverse (35101103022113), we get a palindrome (66223133132266).
The spelling of 31122030110153 in words is "thirty-one trillion, one hundred twenty-two billion, thirty million, one hundred ten thousand, one hundred fifty-three".
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