31122113230213 has 4 divisors (see below), whose sum is σ = 31122128826880. Its totient is φ = 31122097633548.

The previous prime is 31122113230211. The next prime is 31122113230223. The reversal of 31122113230213 is 31203231122113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31122113230213 - 2¹ = 31122113230211 is a prime.

It is a super-4 number, since 4×31122113230213⁴ (a number of 55 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31122113230211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4274373 + ... + 8972986.

It is an arithmetic number, because the mean of its divisors is an integer number (7780532206720).

Almost surely, 2^{31122113230213} is an apocalyptic number.

It is an amenable number.

31122113230213 is a deficient number, since it is larger than the sum of its proper divisors (15596667).

31122113230213 is a wasteful number, since it uses less digits than its factorization.

31122113230213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15596666.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 31122113230213 its reverse (31203231122113), we get a palindrome (62325344352326).

The spelling of 31122113230213 in words is "thirty-one trillion, one hundred twenty-two billion, one hundred thirteen million, two hundred thirty thousand, two hundred thirteen".