311224131414311 has 4 divisors (see below), whose sum is σ = 311224170394824. Its totient is φ = 311224092433800.

The previous prime is 311224131414307. The next prime is 311224131414337. The reversal of 311224131414311 is 113414131422113.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 311224131414311 - 2² = 311224131414307 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311224131414341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2682800 + ... + 25092741.

It is an arithmetic number, because the mean of its divisors is an integer number (77806042598706).

Almost surely, 2^{311224131414311} is an apocalyptic number.

311224131414311 is a deficient number, since it is larger than the sum of its proper divisors (38980513).

311224131414311 is a wasteful number, since it uses less digits than its factorization.

311224131414311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38980512.

The product of its digits is 6912, while the sum is 32.

Adding to 311224131414311 its reverse (113414131422113), we get a palindrome (424638262836424).

The spelling of 311224131414311 in words is "three hundred eleven trillion, two hundred twenty-four billion, one hundred thirty-one million, four hundred fourteen thousand, three hundred eleven".