Base | Representation |
---|---|
bin | 1001000011101100110… |
… | …10100000010111110101 |
3 | 1002202022202102210210100 |
4 | 10201312122200113311 |
5 | 20044341410231031 |
6 | 354550252544313 |
7 | 31325266642131 |
oct | 4416632402765 |
9 | 1082282383710 |
10 | 311224305141 |
11 | 10aa98008942 |
12 | 50398482099 |
13 | 2346b370399 |
14 | 110c5b203c1 |
15 | 8167ca8de6 |
hex | 48766a05f5 |
311224305141 has 24 divisors (see below), whose sum is σ = 451224868640. Its totient is φ = 206708404896.
The previous prime is 311224305089. The next prime is 311224305187. The reversal of 311224305141 is 141503422113.
311224305141 is a `hidden beast` number, since 3 + 112 + 2 + 4 + 30 + 514 + 1 = 666.
It is not a de Polignac number, because 311224305141 - 213 = 311224296949 is a prime.
It is a super-2 number, since 2×3112243051412 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311224303141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 17889075 + ... + 17906463.
Almost surely, 2311224305141 is an apocalyptic number.
It is an amenable number.
311224305141 is a deficient number, since it is larger than the sum of its proper divisors (140000563499).
311224305141 is a wasteful number, since it uses less digits than its factorization.
311224305141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24705 (or 24702 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 311224305141 its reverse (141503422113), we get a palindrome (452727727254).
The spelling of 311224305141 in words is "three hundred eleven billion, two hundred twenty-four million, three hundred five thousand, one hundred forty-one".
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