3112311320221 has 4 divisors (see below), whose sum is σ = 3276117179200. Its totient is φ = 2948505461244.

The previous prime is 3112311320219. The next prime is 3112311320257. The reversal of 3112311320221 is 1220231132113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3112311320221 - 2¹ = 3112311320219 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3112311320192 and 3112311320201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3112311320821) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81902929461 + ... + 81902929498.

It is an arithmetic number, because the mean of its divisors is an integer number (819029294800).

Almost surely, 2^{3112311320221} is an apocalyptic number.

It is an amenable number.

3112311320221 is a deficient number, since it is larger than the sum of its proper divisors (163805858979).

3112311320221 is a wasteful number, since it uses less digits than its factorization.

3112311320221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 163805858978.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 3112311320221 its reverse (1220231132113), we get a palindrome (4332542452334).

The spelling of 3112311320221 in words is "three trillion, one hundred twelve billion, three hundred eleven million, three hundred twenty thousand, two hundred twenty-one".