Base | Representation |
---|---|
bin | 101101010010100100001… |
… | …101011110111011000001 |
3 | 102000112102022211111011011 |
4 | 231102210031132323001 |
5 | 401443003144222012 |
6 | 10341435344520521 |
7 | 440566655504416 |
oct | 55224415367301 |
9 | 12015368744134 |
10 | 3112311320257 |
11 | a9aa18669a17 |
12 | 42322a920141 |
13 | 197649b36719 |
14 | aa8cb05410d |
15 | 55e596e71a7 |
hex | 2d4a435eec1 |
3112311320257 has 2 divisors, whose sum is σ = 3112311320258. Its totient is φ = 3112311320256.
The previous prime is 3112311320219. The next prime is 3112311320269. The reversal of 3112311320257 is 7520231132113.
3112311320257 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2008685432961 + 1103625887296 = 1417281^2 + 1050536^2 .
It is a cyclic number.
It is not a de Polignac number, because 3112311320257 - 219 = 3112310795969 is a prime.
It is not a weakly prime, because it can be changed into another prime (3112311320357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556155660128 + 1556155660129.
It is an arithmetic number, because the mean of its divisors is an integer number (1556155660129).
Almost surely, 23112311320257 is an apocalyptic number.
It is an amenable number.
3112311320257 is a deficient number, since it is larger than the sum of its proper divisors (1).
3112311320257 is an equidigital number, since it uses as much as digits as its factorization.
3112311320257 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7560, while the sum is 31.
The spelling of 3112311320257 in words is "three trillion, one hundred twelve billion, three hundred eleven million, three hundred twenty thousand, two hundred fifty-seven".
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