Search a number
-
+
31124014234 = 215562007117
BaseRepresentation
bin11100111111001000…
…101100010010011010
32222100002022202000221
4130333020230102122
51002220221423414
622144223350254
72151165520165
oct347710542232
988302282027
1031124014234
1112221770615
12604745238a
132c20203391
141713838adc
15c22655224
hex73f22c49a

31124014234 has 4 divisors (see below), whose sum is σ = 46686021354. Its totient is φ = 15562007116.

The previous prime is 31124014219. The next prime is 31124014241. The reversal of 31124014234 is 43241042113.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43241042113 = 83520976411.

It can be written as a sum of positive squares in only one way, i.e., 29979883609 + 1144130625 = 173147^2 + 33825^2 .

It is a junction number, because it is equal to n+sod(n) for n = 31124014199 and 31124014208.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7781003557 + ... + 7781003560.

Almost surely, 231124014234 is an apocalyptic number.

31124014234 is a deficient number, since it is larger than the sum of its proper divisors (15562007120).

31124014234 is a wasteful number, since it uses less digits than its factorization.

31124014234 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15562007119.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 31124014234 its reverse (43241042113), we get a palindrome (74365056347).

The spelling of 31124014234 in words is "thirty-one billion, one hundred twenty-four million, fourteen thousand, two hundred thirty-four".

Divisors: 1 2 15562007117 31124014234