Base | Representation |
---|---|
bin | 101101010010101011011… |
… | …110001101000011001110 |
3 | 102000112201211001202221011 |
4 | 231102223132031003032 |
5 | 401443230341102024 |
6 | 10341455415555434 |
7 | 440602665132625 |
oct | 55225336150316 |
9 | 12015654052834 |
10 | 3112433144014 |
11 | a9aa80406a07 |
12 | 42326368bb7a |
13 | 19766914b79c |
14 | aa8dd2c66bc |
15 | 55e6525d094 |
hex | 2d4ab78d0ce |
3112433144014 has 4 divisors (see below), whose sum is σ = 4668649716024. Its totient is φ = 1556216572006.
The previous prime is 3112433143997. The next prime is 3112433144039. The reversal of 3112433144014 is 4104413342113.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 778108286002 + ... + 778108286005.
It is an arithmetic number, because the mean of its divisors is an integer number (1167162429006).
Almost surely, 23112433144014 is an apocalyptic number.
3112433144014 is a deficient number, since it is larger than the sum of its proper divisors (1556216572010).
3112433144014 is a wasteful number, since it uses less digits than its factorization.
3112433144014 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1556216572009.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 3112433144014 its reverse (4104413342113), we get a palindrome (7216846486127).
The spelling of 3112433144014 in words is "three trillion, one hundred twelve billion, four hundred thirty-three million, one hundred forty-four thousand, fourteen".
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