Base | Representation |
---|---|
bin | 1110001001110101101101… |
… | …10101010000101100000001 |
3 | 11002012110111222111102020010 |
4 | 13010322312311100230001 |
5 | 13034420233003121423 |
6 | 150110204022535133 |
7 | 6361443441430026 |
oct | 704726665205401 |
9 | 132173458442203 |
10 | 31124400442113 |
11 | 9a0a869702390 |
12 | 35a814a8974a9 |
13 | 144a03147b444 |
14 | 79860132b54d |
15 | 38e93c9ba693 |
hex | 1c4eb6d50b01 |
31124400442113 has 128 divisors (see below), whose sum is σ = 49322510254080. Its totient is φ = 17265902734080.
The previous prime is 31124400442103. The next prime is 31124400442139.
It is a happy number.
31124400442113 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 31124400442113 - 218 = 31124400179969 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (31124400442103) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 519758308 + ... + 519818186.
It is an arithmetic number, because the mean of its divisors is an integer number (385332111360).
Almost surely, 231124400442113 is an apocalyptic number.
31124400442113 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
31124400442113 is a deficient number, since it is larger than the sum of its proper divisors (18198109811967).
31124400442113 is a wasteful number, since it uses less digits than its factorization.
31124400442113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 60259.
The product of its (nonzero) digits is 9216, while the sum is 30.
It can be divided in two parts, 31124400 and 442113, that added together give a palindrome (31566513).
The spelling of 31124400442113 in words is "thirty-one trillion, one hundred twenty-four billion, four hundred million, four hundred forty-two thousand, one hundred thirteen".
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