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311244263541257 is a prime number
BaseRepresentation
bin100011011000100110011001…
…1110001000100101000001001
31111211000122211212112211020212
41012301030303301010220021
5311243411222431310012
63021543350223130505
7122362440666545564
oct10661146361045011
91454018755484225
10311244263541257
1190198a50714292
122aaa9282143a35
13104892922c3067
1456c04349b34db
1525eb29e405b22
hex11b1333c44a09

311244263541257 has 2 divisors, whose sum is σ = 311244263541258. Its totient is φ = 311244263541256.

The previous prime is 311244263541229. The next prime is 311244263541313. The reversal of 311244263541257 is 752145362442113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 277209979341376 + 34034284199881 = 16649624^2 + 5833891^2 .

It is an emirp because it is prime and its reverse (752145362442113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 311244263541257 - 212 = 311244263537161 is a prime.

It is a super-2 number, since 2×3112442635412572 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (311244268541257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155622131770628 + 155622131770629.

It is an arithmetic number, because the mean of its divisors is an integer number (155622131770629).

Almost surely, 2311244263541257 is an apocalyptic number.

It is an amenable number.

311244263541257 is a deficient number, since it is larger than the sum of its proper divisors (1).

311244263541257 is an equidigital number, since it uses as much as digits as its factorization.

311244263541257 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4838400, while the sum is 50.

The spelling of 311244263541257 in words is "three hundred eleven trillion, two hundred forty-four billion, two hundred sixty-three million, five hundred forty-one thousand, two hundred fifty-seven".