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311255060552113 is a prime number
BaseRepresentation
bin100011011000101011011011…
…1010100011001100110110001
31111211001200201100000210201211
41012301112313110121212301
5311244100331000131423
63021552333440400121
7122363302362614416
oct10661266724314661
91454050640023654
10311255060552113
11901a2591308357
122aaab396016041
131048a2c3157992
1456c0b7a92410d
1525eb6d224a10d
hex11b15b75199b1

311255060552113 has 2 divisors, whose sum is σ = 311255060552114. Its totient is φ = 311255060552112.

The previous prime is 311255060552071. The next prime is 311255060552159.

311255060552113 is nontrivially palindromic in base 10.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 307045435834944 + 4209624717169 = 17522712^2 + 2051737^2 .

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 311255060552113 - 229 = 311254523681201 is a prime.

It is a super-3 number, since 3×3112550605521133 (a number of 44 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (311255060552213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155627530276056 + 155627530276057.

It is an arithmetic number, because the mean of its divisors is an integer number (155627530276057).

Almost surely, 2311255060552113 is an apocalyptic number.

It is an amenable number.

311255060552113 is a deficient number, since it is larger than the sum of its proper divisors (1).

311255060552113 is an equidigital number, since it uses as much as digits as its factorization.

311255060552113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 135000, while the sum is 40.

The spelling of 311255060552113 in words is "three hundred eleven trillion, two hundred fifty-five billion, sixty million, five hundred fifty-two thousand, one hundred thirteen".