Base | Representation |
---|---|
bin | 1110001001111001100001… |
… | …01010100101000000100001 |
3 | 11002012122210102200101112120 |
4 | 13010330300222211000201 |
5 | 13034433424240241423 |
6 | 150111142521214453 |
7 | 6361545211342020 |
oct | 704746052450041 |
9 | 132178712611476 |
10 | 31126444462113 |
11 | 9a10718485910 |
12 | 35a861b331429 |
13 | 144a298a99030 |
14 | 7987569a48b7 |
15 | 38ea0c175ee3 |
hex | 1c4f30aa5021 |
31126444462113 has 32 divisors (see below), whose sum is σ = 55722865615872. Its totient is φ = 14925767572800.
The previous prime is 31126444462081. The next prime is 31126444462129.
31126444462113 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 31126444462113 - 25 = 31126444462081 is a prime.
It is not an unprimeable number, because it can be changed into a prime (31126444462163) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5182555183 + ... + 5182561188.
It is an arithmetic number, because the mean of its divisors is an integer number (1741339550496).
Almost surely, 231126444462113 is an apocalyptic number.
31126444462113 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
31126444462113 is a deficient number, since it is larger than the sum of its proper divisors (24596421153759).
31126444462113 is a wasteful number, since it uses less digits than its factorization.
31126444462113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10365116405.
The product of its digits is 331776, while the sum is 42.
It can be divided in two parts, 3112644 and 4462113, that added together give a palindrome (7574757).
The spelling of 31126444462113 in words is "thirty-one trillion, one hundred twenty-six billion, four hundred forty-four million, four hundred sixty-two thousand, one hundred thirteen".
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