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3112800497 is a prime number
BaseRepresentation
bin1011100110001001…
…1001000011110001
322000221021122112022
42321202121003301
522333334103442
61232514041225
7140065240052
oct27142310361
98027248468
103112800497
1113581050a4
1272a579215
133a7b8a4b1
142175aa729
151334263d2
hexb98990f1

3112800497 has 2 divisors, whose sum is σ = 3112800498. Its totient is φ = 3112800496.

The previous prime is 3112800479. The next prime is 3112800511. The reversal of 3112800497 is 7940082113.

Together with previous prime (3112800479) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2422214656 + 690585841 = 49216^2 + 26279^2 .

It is an emirp because it is prime and its reverse (7940082113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3112800497 - 26 = 3112800433 is a prime.

It is not a weakly prime, because it can be changed into another prime (3112806497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556400248 + 1556400249.

It is an arithmetic number, because the mean of its divisors is an integer number (1556400249).

Almost surely, 23112800497 is an apocalyptic number.

It is an amenable number.

3112800497 is a deficient number, since it is larger than the sum of its proper divisors (1).

3112800497 is an equidigital number, since it uses as much as digits as its factorization.

3112800497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 35.

The square root of 3112800497 is about 55792.4770645649. The cubic root of 3112800497 is about 1460.1039046900.

The spelling of 3112800497 in words is "three billion, one hundred twelve million, eight hundred thousand, four hundred ninety-seven".