Base | Representation |
---|---|
bin | 1001000011110101000… |
… | …00111001111110000001 |
3 | 1002202111112212112020011 |
4 | 10201322200321332001 |
5 | 20100012012413323 |
6 | 355001151144521 |
7 | 31330063423102 |
oct | 4417240717601 |
9 | 1082445775204 |
10 | 311293091713 |
11 | 11002292024a |
12 | 503b7515141 |
13 | 2347c6a57b6 |
14 | 110d0d083a9 |
15 | 816dd4520d |
hex | 487a839f81 |
311293091713 has 2 divisors, whose sum is σ = 311293091714. Its totient is φ = 311293091712.
The previous prime is 311293091699. The next prime is 311293091833. The reversal of 311293091713 is 317190392113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 308478046464 + 2815045249 = 555408^2 + 53057^2 .
It is a cyclic number.
It is not a de Polignac number, because 311293091713 - 233 = 302703157121 is a prime.
It is not a weakly prime, because it can be changed into another prime (311293098713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155646545856 + 155646545857.
It is an arithmetic number, because the mean of its divisors is an integer number (155646545857).
Almost surely, 2311293091713 is an apocalyptic number.
It is an amenable number.
311293091713 is a deficient number, since it is larger than the sum of its proper divisors (1).
311293091713 is an equidigital number, since it uses as much as digits as its factorization.
311293091713 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30618, while the sum is 40.
The spelling of 311293091713 in words is "three hundred eleven billion, two hundred ninety-three million, ninety-one thousand, seven hundred thirteen".
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