3112970437 has 4 divisors (see below), whose sum is σ = 3122208076. Its totient is φ = 3103732800.

The previous prime is 3112970381. The next prime is 3112970447. The reversal of 3112970437 is 7340792113.

It is a happy number.

It is a Cunningham number, because it is equal to 55794²+1.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 7340792113 = 167 ⋅43956839.

It can be written as a sum of positive squares in 2 ways, for example, as 839492676 + 2273477761 = 28974^2 + 47681^2 .

It is a cyclic number.

It is not a de Polignac number, because 3112970437 - 2⁷ = 3112970309 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3112970396 and 3112970405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3112970447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4618314 + ... + 4618987.

It is an arithmetic number, because the mean of its divisors is an integer number (780552019).

Almost surely, 2^3112970437 is an apocalyptic number.

It is an amenable number.

3112970437 is a deficient number, since it is larger than the sum of its proper divisors (9237639).

3112970437 is an equidigital number, since it uses as much as digits as its factorization.

3112970437 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9237638.

The product of its (nonzero) digits is 31752, while the sum is 37.

The square root of 3112970437 is about 55794.0000089615. Note that the first 5 decimals coincide. The cubic root of 3112970437 is about 1460.1304751413.

The spelling of 3112970437 in words is "three billion, one hundred twelve million, nine hundred seventy thousand, four hundred thirty-seven".