311300000000001 has 24 divisors (see below), whose sum is σ = 464163304340736. Its totient is φ = 200837528053920.

The previous prime is 311299999999987. The next prime is 311300000000027. The reversal of 311300000000001 is 100000000003113.

It is not a de Polignac number, because 311300000000001 - 2¹¹ = 311299999997953 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (311300000002001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 45522046 + ... + 51912008.

It is an arithmetic number, because the mean of its divisors is an integer number (19340137680864).

Almost surely, 2^{311300000000001} is an apocalyptic number.

311300000000001 is a gapful number since it is divisible by the number (31) formed by its first and last digit.

It is an amenable number.

311300000000001 is a deficient number, since it is larger than the sum of its proper divisors (152863304340735).

311300000000001 is a wasteful number, since it uses less digits than its factorization.

311300000000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6564613 (or 6564610 counting only the distinct ones).

The product of its (nonzero) digits is 9, while the sum is 9.

Adding to 311300000000001 its reverse (100000000003113), we get a palindrome (411300000003114).

The spelling of 311300000000001 in words is "three hundred eleven trillion, three hundred billion, one", and thus it is an aban number.