Base | Representation |
---|---|
bin | 100011011001000000010110… |
… | …1111010110010100000000000 |
3 | 1111211012222201020112021220122 |
4 | 1012302000231322302200000 |
5 | 311300314400000000000 |
6 | 3022025125024555412 |
7 | 122366453125616054 |
oct | 10662005572624000 |
9 | 1454188636467818 |
10 | 311300000000000 |
11 | 9020a652475730 |
12 | 2aab8038182b68 |
13 | 1049160565776b |
14 | 56c300110dc64 |
15 | 25ec9626c7085 |
hex | 11b202deb2800 |
311300000000000 has 576 divisors, whose sum is σ = 851791988698560. Its totient is φ = 112800000000000.
The previous prime is 311299999999987. The next prime is 311300000000027. The reversal of 311300000000000 is 3113.
It is a Harshad number since it is a multiple of its sum of digits (8).
It is a junction number, because it is equal to n+sod(n) for n = 311299999999897 and 311299999999906.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1099999999859 + ... + 1100000000141.
It is an arithmetic number, because the mean of its divisors is an integer number (1478805535935).
Almost surely, 2311300000000000 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 311300000000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (425895994349280).
311300000000000 is an abundant number, since it is smaller than the sum of its proper divisors (540491988698560).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
311300000000000 is an frugal number, since it uses more digits than its factorization.
311300000000000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 371 (or 301 counting only the distinct ones).
The product of its (nonzero) digits is 9, while the sum is 8.
Adding to 311300000000000 its reverse (3113), we get a palindrome (311300000003113).
311300000000000 divided by its reverse (3113) gives a 11-th power (100000000000 = 1011).
It can be divided in two parts, 31 and 1300000000000, that added together give a palindrome (1300000000031).
The spelling of 311300000000000 in words is "three hundred eleven trillion, three hundred billion", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •