Base | Representation |
---|---|
bin | 100011011001000000100000… |
… | …0100001110001111100001001 |
3 | 1111211020000112000000021011202 |
4 | 1012302001000201301330021 |
5 | 311300321014411224314 |
6 | 3022025220020433545 |
7 | 122366463636434606 |
oct | 10662010041617411 |
9 | 1454200460007152 |
10 | 311300312211209 |
11 | 9020a7a272a622 |
12 | 2aab81048488b5 |
13 | 1049165523c719 |
14 | 56c30307816ad |
15 | 25ec97ece90de |
hex | 11b2040871f09 |
311300312211209 has 2 divisors, whose sum is σ = 311300312211210. Its totient is φ = 311300312211208.
The previous prime is 311300312211137. The next prime is 311300312211257. The reversal of 311300312211209 is 902112213003113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 235701252079225 + 75599060131984 = 15352565^2 + 8694772^2 .
It is a cyclic number.
It is not a de Polignac number, because 311300312211209 - 228 = 311300043775753 is a prime.
It is not a weakly prime, because it can be changed into another prime (311300312211289) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155650156105604 + 155650156105605.
It is an arithmetic number, because the mean of its divisors is an integer number (155650156105605).
Almost surely, 2311300312211209 is an apocalyptic number.
It is an amenable number.
311300312211209 is a deficient number, since it is larger than the sum of its proper divisors (1).
311300312211209 is an equidigital number, since it uses as much as digits as its factorization.
311300312211209 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 29.
The spelling of 311300312211209 in words is "three hundred eleven trillion, three hundred billion, three hundred twelve million, two hundred eleven thousand, two hundred nine".
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