3113004012 has 12 divisors (see below), whose sum is σ = 7263676056. Its totient is φ = 1037668000.

The previous prime is 3113004001. The next prime is 3113004019. The reversal of 3113004012 is 2104003113.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-2 number, since 2×3113004012² = 19381587957456192288, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3113003982 and 3113004000.

It is not an unprimeable number, because it can be changed into a prime (3113004019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 129708489 + ... + 129708512.

It is an arithmetic number, because the mean of its divisors is an integer number (605306338).

Almost surely, 2^3113004012 is an apocalyptic number.

It is an amenable number.

3113004012 is an abundant number, since it is smaller than the sum of its proper divisors (4150672044).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3113004012 is a wasteful number, since it uses less digits than its factorization.

3113004012 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 259417008 (or 259417006 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 3113004012 is about 55794.3008917578. The cubic root of 3113004012 is about 1460.1357245438.

Adding to 3113004012 its reverse (2104003113), we get a palindrome (5217007125).

The spelling of 3113004012 in words is "three billion, one hundred thirteen million, four thousand, twelve".