3113004103 has 4 divisors (see below), whose sum is σ = 3396004488. Its totient is φ = 2830003720.

The previous prime is 3113004077. The next prime is 3113004127. The reversal of 3113004103 is 3014003113.

3113004103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3014003113 = 11 ⋅274000283.

It is a cyclic number.

It is not a de Polignac number, because 3113004103 - 2¹⁷ = 3112873031 is a prime.

It is a Duffinian number.

It is a plaindrome in base 15.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3113004203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141500176 + ... + 141500197.

It is an arithmetic number, because the mean of its divisors is an integer number (849001122).

Almost surely, 2^3113004103 is an apocalyptic number.

3113004103 is a deficient number, since it is larger than the sum of its proper divisors (283000385).

3113004103 is a wasteful number, since it uses less digits than its factorization.

3113004103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 283000384.

The product of its (nonzero) digits is 108, while the sum is 16.

The square root of 3113004103 is about 55794.3017072532. The cubic root of 3113004103 is about 1460.1357387715.

Adding to 3113004103 its reverse (3014003113), we get a palindrome (6127007216).

The spelling of 3113004103 in words is "three billion, one hundred thirteen million, four thousand, one hundred three".