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31130244343 = 1113156937967
BaseRepresentation
bin11100111111100000…
…011101010011110111
32222100112001021010201
4130333200131103313
51002223320304333
622145005101331
72151302465602
oct347740352367
988315037121
1031130244343
1112225236370
126049557847
132c215a5033
1417145bb339
15c22e8617d
hex73f81d4f7

31130244343 has 16 divisors (see below), whose sum is σ = 34280547840. Its totient is φ = 28034094400.

The previous prime is 31130244337. The next prime is 31130244349. The reversal of 31130244343 is 34344203113.

It is an interprime number because it is at equal distance from previous prime (31130244337) and next prime (31130244349).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31130244343 is a prime.

It is a super-2 number, since 2×311302443432 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31130244349) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 800946 + ... + 838912.

It is an arithmetic number, because the mean of its divisors is an integer number (2142534240).

Almost surely, 231130244343 is an apocalyptic number.

31130244343 is a deficient number, since it is larger than the sum of its proper divisors (3150303497).

31130244343 is a wasteful number, since it uses less digits than its factorization.

31130244343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38678.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 31130244343 its reverse (34344203113), we get a palindrome (65474447456).

The spelling of 31130244343 in words is "thirty-one billion, one hundred thirty million, two hundred forty-four thousand, three hundred forty-three".

Divisors: 1 11 131 569 1441 6259 37967 74539 417637 819929 4973677 21603223 54710447 237635453 2830022213 31130244343