Base | Representation |
---|---|
bin | 11100111111100000… |
… | …011101010011110111 |
3 | 2222100112001021010201 |
4 | 130333200131103313 |
5 | 1002223320304333 |
6 | 22145005101331 |
7 | 2151302465602 |
oct | 347740352367 |
9 | 88315037121 |
10 | 31130244343 |
11 | 12225236370 |
12 | 6049557847 |
13 | 2c215a5033 |
14 | 17145bb339 |
15 | c22e8617d |
hex | 73f81d4f7 |
31130244343 has 16 divisors (see below), whose sum is σ = 34280547840. Its totient is φ = 28034094400.
The previous prime is 31130244337. The next prime is 31130244349. The reversal of 31130244343 is 34344203113.
It is an interprime number because it is at equal distance from previous prime (31130244337) and next prime (31130244349).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31130244343 is a prime.
It is a super-2 number, since 2×311302443432 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31130244349) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 800946 + ... + 838912.
It is an arithmetic number, because the mean of its divisors is an integer number (2142534240).
Almost surely, 231130244343 is an apocalyptic number.
31130244343 is a deficient number, since it is larger than the sum of its proper divisors (3150303497).
31130244343 is a wasteful number, since it uses less digits than its factorization.
31130244343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38678.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 31130244343 its reverse (34344203113), we get a palindrome (65474447456).
The spelling of 31130244343 in words is "thirty-one billion, one hundred thirty million, two hundred forty-four thousand, three hundred forty-three".
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