Base | Representation |
---|---|
bin | 1110001010000010000001… |
… | …11111011011100001001111 |
3 | 11002020002120211210222102121 |
4 | 13011001000333123201033 |
5 | 13040022303403043043 |
6 | 150113220132033411 |
7 | 6362066350155364 |
oct | 705010077334117 |
9 | 132202524728377 |
10 | 31131013331023 |
11 | 9a12652494731 |
12 | 35a9495462867 |
13 | 144a846506568 |
14 | 798a6b6ba46b |
15 | 38ebc8319ded |
hex | 1c5040fdb84f |
31131013331023 has 4 divisors (see below), whose sum is σ = 31138932697288. Its totient is φ = 31123093964760.
The previous prime is 31131013331009. The next prime is 31131013331029. The reversal of 31131013331023 is 32013331013113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31131013331023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31131013331029) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3959677236 + ... + 3959685097.
It is an arithmetic number, because the mean of its divisors is an integer number (7784733174322).
Almost surely, 231131013331023 is an apocalyptic number.
31131013331023 is a deficient number, since it is larger than the sum of its proper divisors (7919366265).
31131013331023 is an equidigital number, since it uses as much as digits as its factorization.
31131013331023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7919366264.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 31131013331023 its reverse (32013331013113), we get a palindrome (63144344344136).
The spelling of 31131013331023 in words is "thirty-one trillion, one hundred thirty-one billion, thirteen million, three hundred thirty-one thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •