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311310411017 is a prime number
BaseRepresentation
bin1001000011110111000…
…10111110010100001001
31002202112202110102211212
410201323202332110021
520100030431123032
6355003010302505
731330363555514
oct4417342762411
91082482412755
10311310411017
1111003167a521
1250401287a35
132348315a9c8
14110d3335d7b
158170616bb2
hex487b8be509

311310411017 has 2 divisors, whose sum is σ = 311310411018. Its totient is φ = 311310411016.

The previous prime is 311310410993. The next prime is 311310411029. The reversal of 311310411017 is 710114013113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 262370352841 + 48940058176 = 512221^2 + 221224^2 .

It is a cyclic number.

It is not a de Polignac number, because 311310411017 - 218 = 311310148873 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 311310410983 and 311310411001.

It is not a weakly prime, because it can be changed into another prime (311310411077) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155655205508 + 155655205509.

It is an arithmetic number, because the mean of its divisors is an integer number (155655205509).

Almost surely, 2311310411017 is an apocalyptic number.

It is an amenable number.

311310411017 is a deficient number, since it is larger than the sum of its proper divisors (1).

311310411017 is an equidigital number, since it uses as much as digits as its factorization.

311310411017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 23.

The spelling of 311310411017 in words is "three hundred eleven billion, three hundred ten million, four hundred eleven thousand, seventeen".