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311311202113114 = 2722236514436651
BaseRepresentation
bin100011011001000101100100…
…1100111011101011001011010
31111211021001121221021121012221
41012302023021213131121122
5311301010320220104424
63022034220353054254
7122400330541200010
oct10662131147353132
91454231557247187
10311311202113114
11902143807aa055
122aaba24385738a
131049269c3c9168
1456c3784b928b0
1525ecdbad8b9e4
hex11b22c99dd65a

311311202113114 has 8 divisors (see below), whose sum is σ = 533676346479648. Its totient is φ = 133419086619900.

The previous prime is 311311202113091. The next prime is 311311202113169. The reversal of 311311202113114 is 411311202113113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×3113112021131142 (a number of 30 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11118257218312 + ... + 11118257218339.

It is an arithmetic number, because the mean of its divisors is an integer number (66709543309956).

Almost surely, 2311311202113114 is an apocalyptic number.

311311202113114 is a deficient number, since it is larger than the sum of its proper divisors (222365144366534).

311311202113114 is a wasteful number, since it uses less digits than its factorization.

311311202113114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22236514436660.

The product of its (nonzero) digits is 432, while the sum is 25.

Adding to 311311202113114 its reverse (411311202113113), we get a palindrome (722622404226227).

Subtracting 311311202113114 from its reverse (411311202113113), we obtain a palindrome (99999999999999).

The spelling of 311311202113114 in words is "three hundred eleven trillion, three hundred eleven billion, two hundred two million, one hundred thirteen thousand, one hundred fourteen".

Divisors: 1 2 7 14 22236514436651 44473028873302 155655601056557 311311202113114