Base | Representation |
---|---|
bin | 101101010011010011111… |
… | …100101000101011010100 |
3 | 102000121111010211220112010 |
4 | 231103103330220223110 |
5 | 402001123211211012 |
6 | 10342051034424220 |
7 | 440625552115341 |
oct | 55232374505324 |
9 | 12017433756463 |
10 | 3113112210132 |
11 | aa0299758381 |
12 | 423412b92070 |
13 | 197746a3b662 |
14 | aa9655717c8 |
15 | 55ea4b97c3c |
hex | 2d4d3f28ad4 |
3113112210132 has 48 divisors (see below), whose sum is σ = 7274787609600. Its totient is φ = 1036153678560.
The previous prime is 3113112210119. The next prime is 3113112210133. The reversal of 3113112210132 is 2310122113113.
It is a junction number, because it is equal to n+sod(n) for n = 3113112210099 and 3113112210108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3113112210133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28138419 + ... + 28248837.
It is an arithmetic number, because the mean of its divisors is an integer number (151558075200).
Almost surely, 23113112210132 is an apocalyptic number.
It is an amenable number.
3113112210132 is an abundant number, since it is smaller than the sum of its proper divisors (4161675399468).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3113112210132 is a wasteful number, since it uses less digits than its factorization.
3113112210132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 113916 (or 113914 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 3113112210132 its reverse (2310122113113), we get a palindrome (5423234323245).
The spelling of 3113112210132 in words is "three trillion, one hundred thirteen billion, one hundred twelve million, two hundred ten thousand, one hundred thirty-two".
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