Base | Representation |
---|---|
bin | 1011100110001110… |
… | …0101011000100010 |
3 | 22000221212112101000 |
4 | 2321203211120202 |
5 | 22333424104442 |
6 | 1232524452430 |
7 | 140101011360 |
oct | 27143453042 |
9 | 8027775330 |
10 | 3113113122 |
11 | 13582a8a69 |
12 | 72a6aa116 |
13 | 3a7c69892 |
14 | 21764c630 |
15 | 133488d4c |
hex | b98e5622 |
3113113122 has 64 divisors (see below), whose sum is σ = 7956829440. Its totient is φ = 883778688.
The previous prime is 3113113079. The next prime is 3113113163. The reversal of 3113113122 is 2213113113.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a nude number because it is divisible by every one of its digits.
It is a junction number, because it is equal to n+sod(n) for n = 3113113095 and 3113113104.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 33118 + ... + 85574.
It is an arithmetic number, because the mean of its divisors is an integer number (124325460).
Almost surely, 23113113122 is an apocalyptic number.
It is a practical number, because each smaller number is the sum of distinct divisors of 3113113122, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3978414720).
3113113122 is an abundant number, since it is smaller than the sum of its proper divisors (4843716318).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3113113122 is a wasteful number, since it uses less digits than its factorization.
3113113122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52632 (or 52626 counting only the distinct ones).
The product of its digits is 108, while the sum is 18.
The square root of 3113113122 is about 55795.2786712281. The cubic root of 3113113122 is about 1460.1527834733.
Adding to 3113113122 its reverse (2213113113), we get a palindrome (5326226235).
Subtracting from 3113113122 its reverse (2213113113), we obtain a palindrome (900000009).
It can be divided in two parts, 31131 and 13122, that added together give a triangular number (44253 = T297).
The spelling of 3113113122 in words is "three billion, one hundred thirteen million, one hundred thirteen thousand, one hundred twenty-two".
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