Base | Representation |
---|---|
bin | 101101010011010100100… |
… | …110111111011001000001 |
3 | 102000121111220202000002111 |
4 | 231103110212333121001 |
5 | 402001134032010332 |
6 | 10342052112415321 |
7 | 440626045361011 |
oct | 55232446773101 |
9 | 12017456660074 |
10 | 3113123313217 |
11 | aa02a4a51285 |
12 | 423416847541 |
13 | 197749128328 |
14 | aa966c21c41 |
15 | 55ea5b3c947 |
hex | 2d4d49bf641 |
3113123313217 has 2 divisors, whose sum is σ = 3113123313218. Its totient is φ = 3113123313216.
The previous prime is 3113123313203. The next prime is 3113123313229. The reversal of 3113123313217 is 7123133213113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3065269125681 + 47854187536 = 1750791^2 + 218756^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3113123313217 is a prime.
It is not a weakly prime, because it can be changed into another prime (3113123313257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556561656608 + 1556561656609.
It is an arithmetic number, because the mean of its divisors is an integer number (1556561656609).
Almost surely, 23113123313217 is an apocalyptic number.
It is an amenable number.
3113123313217 is a deficient number, since it is larger than the sum of its proper divisors (1).
3113123313217 is an equidigital number, since it uses as much as digits as its factorization.
3113123313217 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6804, while the sum is 31.
The spelling of 3113123313217 in words is "three trillion, one hundred thirteen billion, one hundred twenty-three million, three hundred thirteen thousand, two hundred seventeen".
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