Base | Representation |
---|---|
bin | 1011100110001110… |
… | …1001110001011111 |
3 | 22000221220110000222 |
4 | 2321203221301133 |
5 | 22333430143403 |
6 | 1232525111555 |
7 | 140101114655 |
oct | 27143516137 |
9 | 8027813028 |
10 | 3113131103 |
11 | 1358310525 |
12 | 72a6b85bb |
13 | 3a7c74b14 |
14 | 217654dd5 |
15 | 13348e338 |
hex | b98e9c5f |
3113131103 has 4 divisors (see below), whose sum is σ = 3296256480. Its totient is φ = 2930005728.
The previous prime is 3113131097. The next prime is 3113131127. The reversal of 3113131103 is 3011313113.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3011313113 = 131 ⋅22987123.
It is a cyclic number.
It is not a de Polignac number, because 3113131103 - 218 = 3112868959 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (17), and also a Moran number because the ratio is a prime number: 183125359 = 3113131103 / (3 + 1 + 1 + 3 + 1 + 3 + 1 + 1 + 0 + 3).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3113131183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91562663 + ... + 91562696.
It is an arithmetic number, because the mean of its divisors is an integer number (824064120).
Almost surely, 23113131103 is an apocalyptic number.
3113131103 is a deficient number, since it is larger than the sum of its proper divisors (183125377).
3113131103 is a wasteful number, since it uses less digits than its factorization.
3113131103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 183125376.
The product of its (nonzero) digits is 81, while the sum is 17.
The square root of 3113131103 is about 55795.4398047009. The cubic root of 3113131103 is about 1460.1555946953.
Adding to 3113131103 its reverse (3011313113), we get a palindrome (6124444216).
It can be divided in two parts, 311313110 and 3, that added together give a palindrome (311313113).
The spelling of 3113131103 in words is "three billion, one hundred thirteen million, one hundred thirty-one thousand, one hundred three".
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