Base | Representation |
---|---|
bin | 100011011001001001110011… |
… | …1111110001011100000001001 |
3 | 1111211021221010002001012202211 |
4 | 1012302103213332023200021 |
5 | 311301132434114221301 |
6 | 3022042323320425121 |
7 | 122401102200161365 |
oct | 10662234776134011 |
9 | 1454257102035684 |
10 | 311320301320201 |
11 | 9021821aaa0008 |
12 | 2aabbb630181a1 |
13 | 104934bc5a3074 |
14 | 56c3da94302a5 |
15 | 25ed24eb13051 |
hex | 11b24e7f8b809 |
311320301320201 has 2 divisors, whose sum is σ = 311320301320202. Its totient is φ = 311320301320200.
The previous prime is 311320301320163. The next prime is 311320301320261. The reversal of 311320301320201 is 102023103023113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 214293762778176 + 97026538542025 = 14638776^2 + 9850205^2 .
It is a cyclic number.
It is not a de Polignac number, because 311320301320201 - 215 = 311320301287433 is a prime.
It is not a weakly prime, because it can be changed into another prime (311320301320261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155660150660100 + 155660150660101.
It is an arithmetic number, because the mean of its divisors is an integer number (155660150660101).
Almost surely, 2311320301320201 is an apocalyptic number.
It is an amenable number.
311320301320201 is a deficient number, since it is larger than the sum of its proper divisors (1).
311320301320201 is an equidigital number, since it uses as much as digits as its factorization.
311320301320201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 311320301320201 its reverse (102023103023113), we get a palindrome (413343404343314).
The spelling of 311320301320201 in words is "three hundred eleven trillion, three hundred twenty billion, three hundred one million, three hundred twenty thousand, two hundred one".
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